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![√（5-x^2）=ln（5-x^2）(ln[根号（x^2+y^2）] =arctany/x 求dy)](https://image.zuidongwo.com/thumbnail/pic3424.jpg)
√（5-x^2）=ln（5-x^2）(ln[根号（x^2+y^2）] =arctany/x 求dy)
ullia href=#BeX5ln[根号（x^2+y^2）] =arctany/x 求dy/a/lilia href=#toJV∫x^2/√(2-x^2)dx？/a/lilia href=#761r（√5＋√2）²－（√5－√2）²/a/lilia ...
ullia href=#BeX5ln[根号（x^2+y^2）] =arctany/x 求dy/a/lilia href=#toJV∫x^2/√(2-x^2)dx？/a/lilia href=#761r（√5＋√2）²－（√5－√2）²/a/lilia ...